Hi It describes the (x) rows describes the number of items retrieved to display in the output and xxxx seconds says the time taken for displaying it. Incase of puts as there are not rows to be retrieved and displayed the (x) rows remains 0, but the xxx seconds says the time it took for doing that operation. If the time calculation is accurate or not am not sure on that. Need to see how it is calculated. Does this answer you question?
Regards Ram On Tue, Feb 11, 2014 at 2:48 PM, Tao Xiao <[email protected]> wrote: > I executed some commands in hbase's shell and got the following results: > > hbase(main):014:0> list > TABLE > > testtable > > 1 row(s) in 0.0180 seconds ### what does "1 row(s)" mean? > > hbase(main):015:0> count 'testtable' > Current count: 1000, row: row-999 > > 1000 row(s) in 0.3300 seconds ### indeed we have 1000 rows in > testtable > > hbase(main):017:0> create 'newtable', 'cf' > 0 row(s) in 1.1450 seconds > > hbase(main):018:0> put 'newtable', 'row1', 'cf:A', 'value1' > 0 row(s) in 0.0120 seconds ### what does "0 row(s)" mean? > > hbase(main):019:0> put 'newtable', 'row2', 'cf:A', 'value2' > 0 row(s) in 0.0080 seconds > > we can see that the shell printed results ending with "xx row(s) in xxx > seconds", what does this mean ? >
