Ok, I see, thanks ramkrishna.
2014-02-11 17:25 GMT+08:00 ramkrishna vasudevan < [email protected]>: > Hi > > It describes the (x) rows describes the number of items retrieved to > display in the output and xxxx seconds says the time taken for displaying > it. > Incase of puts as there are not rows to be retrieved and displayed the (x) > rows remains 0, but the xxx seconds says the time it took for doing that > operation. If the time calculation is accurate or not am not sure on that. > Need to see how it is calculated. > Does this answer you question? > > Regards > Ram > > > On Tue, Feb 11, 2014 at 2:48 PM, Tao Xiao <[email protected]> > wrote: > > > I executed some commands in hbase's shell and got the following results: > > > > hbase(main):014:0> list > > TABLE > > > > testtable > > > > 1 row(s) in 0.0180 seconds ### what does "1 row(s)" mean? > > > > hbase(main):015:0> count 'testtable' > > Current count: 1000, row: row-999 > > > > 1000 row(s) in 0.3300 seconds ### indeed we have 1000 rows in > > testtable > > > > hbase(main):017:0> create 'newtable', 'cf' > > 0 row(s) in 1.1450 seconds > > > > hbase(main):018:0> put 'newtable', 'row1', 'cf:A', 'value1' > > 0 row(s) in 0.0120 seconds ### what does "0 row(s)" mean? > > > > hbase(main):019:0> put 'newtable', 'row2', 'cf:A', 'value2' > > 0 row(s) in 0.0080 seconds > > > > we can see that the shell printed results ending with "xx row(s) in xxx > > seconds", what does this mean ? > > >
