You could use a custom filter (not tested, just written here in the reply):
{
"order" : "depth first",
"uniqueness" : "node",
"relationships" : [{"type" : "abc", "direction" : "out" }],
"return filter" :
{
"language" : "javascript",
"body" : "position.length() > 0 &&
position.lastRelationship().getProperty('number',0) == 1"
},
"max depth" : 1
}
2011/2/10 mike_t <[email protected]>
>
> Hi,
>
> i`m using neo4j with the rest api. I have following question about
> traversing the graph:
>
> Is it possible to get all relationships of a node by a special property?
>
> Example:
>
> Node A has a relationship ("type=abc", property "number=1") to Node B
> Node A has a relationship ("type=def", property "number=1") to Node C
> Node A has a relationship ("type=xyz", property "number=1") to Node D
>
> Now, i wanna have all relationships for Node A with relationship property
> "number=1". The relationship type don´t cares.
>
> When I traverse the graph i have to define the relationship type like:
> curl -X POST -H Accept:application/json -H Content-Type:application/json -d
> '{ "order" : "depth first", "uniqueness" : "node", "relationships" : [{
> "type" : "abc", "direction" : "out" }], "return filter" : { "language" :
> "builtin", "name" : "all" }, "max depth" : 1 }'
> http://localhost:7474/db/data/node/1/traverse/node
>
> Is the only solution to make an index?
>
> Thanks for your answers!
> --
> View this message in context:
> http://neo4j-user-list.438527.n3.nabble.com/Traversing-by-Relationship-property-tp2464461p2464461.html
> Sent from the Neo4J User List mailing list archive at Nabble.com.
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--
Mattias Persson, [[email protected]]
Hacker, Neo Technology
www.neotechnology.com
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