Perhaps leave off the "relationship" restriction. Then you should be able to
get what you want.
Am 10.02.2011 um 12:43 schrieb Mattias Persson:
> You could use a custom filter (not tested, just written here in the reply):
>
> {
> "order" : "depth first",
> "uniqueness" : "node",
> "relationships" : [{"type" : "abc", "direction" : "out" }],
> "return filter" :
> {
> "language" : "javascript",
> "body" : "position.length() > 0 &&
> position.lastRelationship().getProperty('number',0) == 1"
> },
> "max depth" : 1
> }
>
>
> 2011/2/10 mike_t <[email protected]>
>
>>
>> Hi,
>>
>> i`m using neo4j with the rest api. I have following question about
>> traversing the graph:
>>
>> Is it possible to get all relationships of a node by a special property?
>>
>> Example:
>>
>> Node A has a relationship ("type=abc", property "number=1") to Node B
>> Node A has a relationship ("type=def", property "number=1") to Node C
>> Node A has a relationship ("type=xyz", property "number=1") to Node D
>>
>> Now, i wanna have all relationships for Node A with relationship property
>> "number=1". The relationship type don´t cares.
>>
>> When I traverse the graph i have to define the relationship type like:
>> curl -X POST -H Accept:application/json -H Content-Type:application/json -d
>> '{ "order" : "depth first", "uniqueness" : "node", "relationships" : [{
>> "type" : "abc", "direction" : "out" }], "return filter" : { "language" :
>> "builtin", "name" : "all" }, "max depth" : 1 }'
>> http://localhost:7474/db/data/node/1/traverse/node
>>
>> Is the only solution to make an index?
>>
>> Thanks for your answers!
>> --
>> View this message in context:
>> http://neo4j-user-list.438527.n3.nabble.com/Traversing-by-Relationship-property-tp2464461p2464461.html
>> Sent from the Neo4J User List mailing list archive at Nabble.com.
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>
>
>
> --
> Mattias Persson, [[email protected]]
> Hacker, Neo Technology
> www.neotechnology.com
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