Thus, in order to get all the singular vectors, I have to do two mahout SVD. One with the original matrix, the other with the transpose A'. Is that right?
________________________________ From: Ted Dunning <[email protected]> To: [email protected] Cc: Dan Brickley <[email protected]> Sent: Friday, February 25, 2011 12:36 PM Subject: Re: Understanding Mahout's Hadoop SVD results - eigenvectors/values vs decomposed matrices Generally the SVD in these sorts of situations does not return the entire set of three matrices. Instead either the left or right (but usually the right) eigenvectors premultiplied by the diagonal or the square root of the diagonal element. I can't comment specifically on your situation, but hopefully knowing that the algorithm isn't supposed to return all three matrices will help you. On Fri, Feb 25, 2011 at 7:37 AM, Dan Brickley <[email protected]> wrote: > My problem is that I was imagining the results would be three factor'd > matrixes (which when multiplied would reproduce the original, and from > which I could take left-most columns per various SVD tutorials). >
