No. You can multiply the original matrix by the transpose of the available eigenvectors and the inverse of the eigenvalues to get the missing eigenvectors. No iterations or fancy math needed.
On Fri, Feb 25, 2011 at 10:08 AM, Zhengguo 'Mike' SUN <[email protected] > wrote: > Thus, in order to get all the singular vectors, I have to do two mahout > SVD. One with the original matrix, the other with the transpose A'. Is that > right? >
