Hi,
hmmm, that's strange. When I apply the rules on the document "A B C D",
only one T1 annotation remains.
On which document did you test the rules?
Best,
Peter
Am 20.02.2015 um 09:17 schrieb Silvestre Losada:
HI again,
Now I'm running into this problem
DECLARE T1;
"A B C D" -> T1;
"B" -> T1;
"C D" -> T1;
"D" -> T1;
(T1{-> UNMARKALL(T1)}){PARTOFNEQ(T1)};
The ouput is
"A B C D" -> T1;
"D" -> T1;
I suspect that this is because D is part of "A B C D" and "C D"
Im using lastest version in trunk.
Kind regards
On 14 February 2015 at 09:29, Silvestre Losada <[email protected]>
wrote:
Thanks Peter,
It seems to work.
On 13 February 2015 at 22:18, Peter Klügl <[email protected]>
wrote:
This should work just fine and should remove both contained annotations.
I just tested it with the current trunk and the following script:
DECLARE T1;
"A B" -> T1;
"B" -> T1;
"B" -> T1;
(T1{-> UNMARK(T1)}){PARTOFNEQ(T1)};
If applied on the test "A B", only the largest annotation remains.
Can you test it with the current trunk in case I fixed the bug a few
minutes ago by accident. If not, can you give me more information about the
context of your rule?
Best,
Peter
Am 12.02.2015 um 10:12 schrieb Silvestre Losada:
I dont know if this is a bug or if it is wokring well. I have the
following
annotations.
AnnotationA
begin:0
ends:8
id:1
AnnotationA
begin:4
ends:8
id:2
AnnotationA
begin: 4
ends:8
id:3
Then if apply the following ruta
(AnnotationA{-> UNMARK(AnnotationA)}){PARTOFNEQ(AnnotationA)};
The output is
AnnotationA
begin:0
ends:8
id:1
AnnotationA
begin: 4
ends:8
id:3
I expect that annotations with id 2 and 3 will be removed. Is there any
way
to remove both
Kind regards
