:-O What a mistake on my part ! Sorry for that ... Everything works pretty well now. Thank you Radu for your great help.
Regards Pascal On Fri, May 2, 2008 at 2:07 AM, Radu Preotiuc-Pietro <[EMAIL PROTECTED]> wrote: > Hi Pascal, > > You have to decide whether "uri" is an element or an attribute. In your > original example it was an attribute, but in the Schema you send it shows > it's an element. If it is element, obviously, your XML would have to look > like (it has nothing to do with fragments): > > String xml = "<ns:element xmlns:ns=\" > http://www.example.org/docelement\ <http://www.example.org/docelement%5C> > "><ns:uri>www.apache.org</ns:uri></ns:element>"; > Radu > > ------------------------------ > *From:* Pascal Maugeri [mailto:[EMAIL PROTECTED] > *Sent:* Thursday, May 01, 2008 1:54 PM > > *To:* user@xmlbeans.apache.org > *Subject:* Re: Parsing an XML fragment > > Hi Radu > > There is some progress here... > > I did modified the xml as you recommended and the following code: > > String xml = "<ns:element uri=\"www.apache.org\" xmlns:ns=\" > http://www.example.org/docelement\ <http://www.example.org/docelement%5C> > "/>"; > XmlOptions xmlOptions = new > XmlOptions().setDocumentType(DocDocument.Doc.type); > DocDocument.Doc doc = (DocDocument.Doc) > XmlObject.Factory.parse(xml, xmlOptions); > System.out.println(doc.toString()); > System.out.println(doc.getElement().toString()); > System.out.println(doc.getElement().getUri()); > > outputs: > > <ns:element uri="www.apache.org" xmlns:ns=" > http://www.example.org/docelement"/> > <xml-fragment uri="www.apache.org" xmlns:ns=" > http://www.example.org/docelement"/> > null > > As you can see the doc.getElement.getUri() still returns null :-( > > I've played around with the schema, for instance I switched > elementFormDefault to "unqualified": > > String xml = "<element uri=\"www.apache.org\"/>"; > XmlOptions xmlOptions = new > XmlOptions().setDocumentType(DocDocument.Doc.type); > DocDocument.Doc doc = (DocDocument.Doc) > XmlObject.Factory.parse(xml, xmlOptions); > System.out.println(doc.toString()); > System.out.println(doc.getElement().toString()); > System.out.println(doc.getElement().getUri()); > > outputs: > > <element uri="www.apache.org"/> > <xml-fragment uri="www.apache.org"/> > null > > I get the same results (doc.getElement().getUri() is null). > > I also tried with attributeFormDefault="unqualified" with no success > neither: > > String xml = "<ns:element ns:uri=\"www.apache.org\" xmlns:ns=\" > http://www.example.org/docelement\ <http://www.example.org/docelement%5C> > "/>"; > XmlOptions xmlOptions = new > XmlOptions().setDocumentType(DocDocument.Doc.type); > DocDocument.Doc doc = (DocDocument.Doc) > XmlObject.Factory.parse(xml, xmlOptions); > System.out.println(doc.toString()); > System.out.println(doc.getElement().toString()); > System.out.println(doc.getElement().getUri()); > > Do you have any idea why I can't access the element attribute ? > > Thanks > Pascal > > On Thu, May 1, 2008 at 1:09 AM, Radu Preotiuc-Pietro <[EMAIL PROTECTED]> > wrote: > > > Yep, in your Schema you have elementFormDefault="qualified". So this > > means your doc fragment has to look like: > > > > String xml = "<ns:element uri=\"www.apache.org\" xmlns:ns= > > \"http://www.example.org/docelement\<http://www.example.org/docelement%5C> > > "/>"; > > > > Radu > > > > On Wed, 2008-04-30 at 15:07 +0200, Pascal Maugeri wrote: > > > Hi Radu > > > > > > Sorry again to comment on this issue but I do not find the same > > > results as yours. > > > > > > with the following source code: > > > > > > String xml = "<element uri=\"www.apache.org\"/>"; > > > XmlOptions xmlOptions = new > > > XmlOptions().setDocumentType(DocDocument.Doc.type); > > > DocDocument.Doc doc = (DocDocument.Doc) > > > XmlObject.Factory.parse(xml, xmlOptions); > > > System.out.println(doc.toString()); > > > System.out.println(doc.getElement().toString()); > > > > > > The first sysout prints the correct result: > > > > > > <element uri="www.apache.org"/> > > > > > > The last sysout throws a NullPointerException because doc.getElement() > > > returns null > > > > > > java.lang.NullPointerException > > > at > > > xmlbeans.ParsingXmlFragment.<init>(ParsingXmlFragment.java:17) > > > at xmlbeans.ParsingXmlFragment.main(ParsingXmlFragment.java:22) > > > > > > I've attached to this email the beans jar I've generated and the piece > > > of code I tested. If you want to dedicate more time to this issue it > > > may be interesting to execute it in your environment. Please confirm > > > me that you do not get the exception. > > > > > > Regards, > > > Pascal > > > > > > > > > > > > On Tue, Apr 29, 2008 at 2:27 AM, Radu Preotiuc-Pietro <[EMAIL PROTECTED]> > > > wrote: > > > Actually, I have made some experiments myself and you may have > > > success > > > with something like: > > > > > > DocDocument.Doc doc = (DocDocument.Doc) > > > XmlObject.Factory.parse(new > > > File("test.xml"), new > > > XmlOptions().setDocumentType(DocDocument.Doc.type)); > > > > > > to parse from the <element> level. > > > > > > Let me know if this works for you, > > > Radu > > > > > > > > > > -----Original Message----- > > > > From: Jim the Standing Bear [mailto:[EMAIL PROTECTED] > > > > Sent: Monday, April 28, 2008 8:38 AM > > > > To: user@xmlbeans.apache.org > > > > Subject: Re: Parsing an XML fragment > > > > > > > > I ran into the same problem and toyed around it over the > > > weekend. > > > > what I found out was that it helps if you parse it from "a > > > level up". > > > > > > > > So in your case, you would have to parse it from the > > > Document > > > > level, since that is the only thing above "Element" nodes. > > > > > > > > In other words, doing > > > > Doc.Factory.parse(xml).getDoc().getElement().getUri() is the > > > > way to go. However, you said you needed to parse from > > > > Element level - is there any constraints that force you to > > > > parse from Element level? > > > > > > > > HTH > > > > > > > > Jim > > > > > > > > > > > > > > > > On Mon, Apr 28, 2008 at 6:17 AM, Pascal Maugeri > > > > <[EMAIL PROTECTED]> wrote: > > > > > Radu > > > > > > > > > > You're right in the example below the <element> is not a > > > > global schema type. > > > > > > > > > > So what should I do if a server (XCAP server) sends me > > > this > > > > XML fragment: > > > > > > > > > > > > > > > <element uri="www.apache.org"/> > > > > > > > > > > and I want to parse it having the xml beans set from the > > > > corresponding > > > > > schema ? > > > > > > > > > > Is there a way to do that ? > > > > > > > > > > Regards, > > > > > Pascal > > > > > > > > > > > > > > > > > > > > > > > > > On Sat, Apr 19, 2008 at 3:35 AM, Radu Preotiuc-Pietro > > > > <[EMAIL PROTECTED]> wrote: > > > > > > > > > > > I'd have to see the Schema to be able to figure out the > > > name of > > > > > > elements and types and what the exact code should look > > > > like. I think > > > > > > that your problem might be that <element> is not a > > > global Schema > > > > > > type and so auto-typing doesn't work if at the root > > > level > > > > (in other > > > > > > words, Schema doesn't allow <element> to be a top-level > > > element). > > > > > > > > > > > > But even then, you should not have to parse and save to > > > > String only > > > > > > to parse again. > > > > > > > > > > > > Radu > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > On Tue, 2008-04-08 at 06:49 -0700, Pascal Maugeri wrote: > > > > > > > Hi > > > > > > > > > > > > > > I would like to have a clarification about the parsing > > > of a XML > > > > > > > fragment. > > > > > > > > > > > > > > For instance, having the following XML document, I > > > want > > > > to obtain > > > > > > > the "uri" attribute value: > > > > > > > > > > > > > > <?xml version="1.0" encoding="UTF-8"?> > > > > > > > <doc> > > > > > > > <element uri="www.apache.org"/> > > > > > > > </doc> > > > > > > > > > > > > > > with > > > > > > > > > > Doc.Factory.parse(xml).getDoc().getElement().getUri() > > > > > > > it returns the attribute value. > > > > > > > > > > > > > > but with > > > > > > > Element.Factory.parse("<element > > > > > > > uri=\"www.apache.org\"/>").getUri() > > > > > > > it returns null, also a call to > > > Element.Factory.parse("<element > > > > > > > uri= > > > > > > > \"www.apache.org\"/>").toString() returns the XML > > > content. > > > > > > > > > > > > > > As I do need to parse XML fragment such as this > > > > "element", I have > > > > > > > found the following workaround: > > > > > > > a) I get the String representation of the Element (eg. > > > > > > > Element.Factory.parse(...).toString() ), > > > > > > > b) I insert the result of (a) into a container > > > <doc>...</doc> > > > > > > > c) then I parse the result of (b) with the > > > > Doc.Factory.parse( (b) > > > > > > > ).getDoc().getElement().getUri() and it does work. > > > > > > > ... also I'm not very proud of myself :-) > > > > > > > > > > > > > > Could you explain why I can't access the attributes of > > > a XML > > > > > > > fragment I parsed ? > > > > > > > > > > > > > > I there a better/cleaner workaround than the one > > > above ? > > > > > > > > > > > > > > Thanks in advance for your help > > > > > > > Pascal > > > > > > > > > > > > Notice: This email message, together with any > > > attachments, may > > > > > > contain > > > > > information of BEA Systems, Inc., its subsidiaries > > > and > > > > > affiliated entities, that may be confidential, > > > proprietary, > > > > > copyrighted and/or legally privileged, and is intended > > > > solely for the > > > > > use of the individual or entity named in this message. 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