On Feb 13, 2008 4:17 PM, GeekPro <[EMAIL PROTECTED]> wrote:
> I mean the transportConnector Address..NeverMind I am clear in this but
> comming to our networkConnector
>
> In broker1 the network Connector will have the
>
> uri = "static:(tcp://10.0.0.2:62626)"
>
> In broker2 the network Connector will have th
>
> uri = "static:(tcp://10.0.0.2:61616)"
>
>
> Step 1:
> So from the Subscriber I had 2 instances one is listening to 61616 and the
> other with 62626(with out failover protocol)
OK, you have a subscriber pointing to each broker.
> Here in step1 if the 61616 gets the message then listener with 62626 is not
> getting the messagep
If you're expecting each subscriber to get a copy of the messages
you're sending, you'll need to use topics.
> Step2 :
>
> I have one more instance which is listening to both 61616 and 62626 (with
> failover protocol)
>
> Here if the message goes to 62626 then the listener can't get the message in
> the failover I mentioned 61616 address as the first arg.
Well if you're using failover, then a random connection will be made
one of the brokers. I doubt this is the behavior that you want.
The easiest way to test any topology with ActiveMQ is using the
consumer/producer examples that come with ActiveMQ. I just did this,
in fact. I configured three brokers, brokerA points to brokerB,
brokerB points to brokerA and brokerC, brokerC points to brokerB. So I
have a linear topology that looks like this:
brokerB(61611) <--> brokerB(61612) <--> brokerC(61613)
In one terminal, I cd into the the ActiveMQ example directory and I
run 'ant consumer -Durl=tcp://localhost:61611'. Then in another
terminal, I cd into the ActiveMQ example directory and I run 'ant
producer -Durl=tcp://localhost:61613'. The messages are produced to
brokerC and the consumer on brokerA consumes them. This is a very
basic example but the example consumer and producer that come with
ActiveMQ have many, many options allowing you to test any topology
quite easily.
Bruce
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