Sure. camel-config.xml:
<beans xmlns="http://www.springframework.org/schema/beans"; xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; xsi:schemaLocation=" http://camel.apache.org/schema/spring http://camel.apache.org/schema/spring/camel-spring.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.5.xsd";> <!-- create a camel context as to start Camel --> <camelContext id="camel" xmlns="http://camel.apache.org/schema/spring";> <package>package.contains.route.builder</package> </camelContext> </beans> web.xml: <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; xmlns="http://java.sun.com/xml/ns/javaee"; xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"; xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"; id="WebApp_ID" version="2.5"> <servlet> <servlet-name>CamelServlet</servlet-name> <servlet-class> org.apache.camel.component.servlet.CamelHttpTransportServlet </servlet-class> <init-param> <param-name>matchOnUriPrefix</param-name> <param-value>true</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>CamelServlet</servlet-name> <url-pattern>/services/*</url-pattern> </servlet-mapping> <!-- location of spring xml files --> <context-param> <param-name>contextConfigLocation</param-name> <param-value>classpath:camel-config.xml</param-value> </context-param> <!-- the listener that kick-starts Spring --> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> </web-app> RouteBuilder java class: public class ServletToJmsRouteBuilder extends RouteBuilder { public void configure() throws Exception { from("servlet:///hello?servletName=CamelServlet").process(new Processor() { public void process(Exchange exchange) { String contentType = (String) exchange.getIn().getHeader(Exchange.CONTENT_TYPE, String.class); String path = (String) exchange.getIn().getHeader(Exchange.HTTP_PATH, String.class); String charsetEncoding = (String) exchange.getIn().getHeader(Exchange.HTTP_CHARACTER_ENCODING, String.class); exchange.getOut().setHeader(Exchange.CONTENT_TYPE, contentType + "; charset=UTF-8"); exchange.getOut().setHeader("PATH", path); exchange.getOut().setBody("Hello World"); } }); } } Please let me know if you need anything else. Thanks a lot. willem.jiang wrote: > > Hi, > > Can you show me the camel-config.xml? > A simple demo help me debug the issue. > > Willem > > janylj wrote: >> >> willem.jiang wrote: >>> >>> If you create the servlet component, you need to specify the servlet >>> which the component will attach to. >>> <bean id="servlet" >>> class="org.apache.camel.component.servlet.ServletComponent"> >>> <property name="camelContext" ref="camel" /> >>> <property name="servletName" value="CamelServlet" /> >>> </bean> >>> >>> >> >> doesn't work, because Tomcat starts error said, >> >> Caused by: org.springframework.beans.InvalidPropertyException: Invalid >> property 'servletName' of bean class >> [org.apache.camel.component.servlet.ServletComponent]: No property >> 'servletName' found >> >> >> willem.jiang wrote: >>> >>> You don't need to specify the servlet component in spring, if there is >>> only one camel servlet created in the web context. >>> >>> >> >> doesn't work, because Tomcat starts error said, >> >> Caused by: java.lang.IllegalArgumentException: Can't find the deployied >> servlet, please set the ServletComponent with it or delopy a >> CamelHttpTransportServlet int the web container >> >> What I am missing? Please note that I am using Spring >> ContextLoaderListener. >> Thanks a lot. >> >> my web.xml, >> >> <!-- location of spring xml files --> >> <context-param> >> <param-name>contextConfigLocation</param-name> >> <param-value>classpath:camel-config.xml</param-value> >> </context-param> >> >> <!-- the listener that kick-starts Spring --> >> <listener> >> >> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> >> </listener> >> >> <servlet> >> <servlet-name>CamelServlet</servlet-name> >> <servlet-class> >> >> org.apache.camel.component.servlet.CamelHttpTransportServlet >> </servlet-class> >> <init-param> >> <param-name>matchOnUriPrefix</param-name> >> <param-value>true</param-value> >> </init-param> >> <load-on-startup>1</load-on-startup> >> </servlet> >> >> <servlet-mapping> >> <servlet-name>CamelServlet</servlet-name> >> <url-pattern>/services/*</url-pattern> >> </servlet-mapping> >> >> >> > > > -- View this message in context: http://www.nabble.com/How-to-create-a-Servlet-component--tp24909157p24940161.html Sent from the Camel - Users mailing list archive at Nabble.com.
