Hi Just to inform Camel have the camel-jetty component that allows you to expose a HTTP service and let Camel handle the request and return a reply. http://camel.apache.org/jetty
But you got the right source about the Camel Servlet as it was Willem who wrote it. On Wed, Aug 12, 2009 at 6:28 PM, janylj<jan...@gmail.com> wrote: > > Sure. > > camel-config.xml: > > <beans xmlns="http://www.springframework.org/schema/beans"; > xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; > xsi:schemaLocation=" > http://camel.apache.org/schema/spring > http://camel.apache.org/schema/spring/camel-spring.xsd > http://www.springframework.org/schema/beans > http://www.springframework.org/schema/beans/spring-beans-2.5.xsd";> > > <!-- create a camel context as to start Camel --> > <camelContext id="camel" xmlns="http://camel.apache.org/schema/spring";> > <package>package.contains.route.builder</package> > </camelContext> > </beans> > > web.xml: > <web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"; > xmlns="http://java.sun.com/xml/ns/javaee"; > xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"; > xsi:schemaLocation="http://java.sun.com/xml/ns/javaee > http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"; > id="WebApp_ID" version="2.5"> > > <servlet> > <servlet-name>CamelServlet</servlet-name> > <servlet-class> > > org.apache.camel.component.servlet.CamelHttpTransportServlet > </servlet-class> > <init-param> > <param-name>matchOnUriPrefix</param-name> > <param-value>true</param-value> > </init-param> > <load-on-startup>1</load-on-startup> > </servlet> > > <servlet-mapping> > <servlet-name>CamelServlet</servlet-name> > <url-pattern>/services/*</url-pattern> > </servlet-mapping> > > <!-- location of spring xml files --> > <context-param> > <param-name>contextConfigLocation</param-name> > <param-value>classpath:camel-config.xml</param-value> > </context-param> > > <!-- the listener that kick-starts Spring --> > <listener> > > <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> > </listener> > </web-app> > > RouteBuilder java class: > public class ServletToJmsRouteBuilder extends RouteBuilder { > > public void configure() throws Exception { > from("servlet:///hello?servletName=CamelServlet").process(new > Processor() > { > > public void process(Exchange exchange) { > String contentType = (String) > exchange.getIn().getHeader(Exchange.CONTENT_TYPE, String.class); > String path = (String) > exchange.getIn().getHeader(Exchange.HTTP_PATH, String.class); > String charsetEncoding = (String) > exchange.getIn().getHeader(Exchange.HTTP_CHARACTER_ENCODING, String.class); > exchange.getOut().setHeader(Exchange.CONTENT_TYPE, > contentType + "; charset=UTF-8"); > exchange.getOut().setHeader("PATH", path); > exchange.getOut().setBody("Hello World"); > } > }); > } > } > > Please let me know if you need anything else. Thanks a lot. > > > willem.jiang wrote: >> >> Hi, >> >> Can you show me the camel-config.xml? >> A simple demo help me debug the issue. >> >> Willem >> >> janylj wrote: >>> >>> willem.jiang wrote: >>>> >>>> If you create the servlet component, you need to specify the servlet >>>> which the component will attach to. >>>> <bean id="servlet" >>>> class="org.apache.camel.component.servlet.ServletComponent"> >>>> <property name="camelContext" ref="camel" /> >>>> <property name="servletName" value="CamelServlet" /> >>>> </bean> >>>> >>>> >>> >>> doesn't work, because Tomcat starts error said, >>> >>> Caused by: org.springframework.beans.InvalidPropertyException: Invalid >>> property 'servletName' of bean class >>> [org.apache.camel.component.servlet.ServletComponent]: No property >>> 'servletName' found >>> >>> >>> willem.jiang wrote: >>>> >>>> You don't need to specify the servlet component in spring, if there is >>>> only one camel servlet created in the web context. >>>> >>>> >>> >>> doesn't work, because Tomcat starts error said, >>> >>> Caused by: java.lang.IllegalArgumentException: Can't find the deployied >>> servlet, please set the ServletComponent with it or delopy a >>> CamelHttpTransportServlet int the web container >>> >>> What I am missing? Please note that I am using Spring >>> ContextLoaderListener. >>> Thanks a lot. >>> >>> my web.xml, >>> >>> <!-- location of spring xml files --> >>> <context-param> >>> <param-name>contextConfigLocation</param-name> >>> <param-value>classpath:camel-config.xml</param-value> >>> </context-param> >>> >>> <!-- the listener that kick-starts Spring --> >>> <listener> >>> >>> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> >>> </listener> >>> >>> <servlet> >>> <servlet-name>CamelServlet</servlet-name> >>> <servlet-class> >>> >>> org.apache.camel.component.servlet.CamelHttpTransportServlet >>> </servlet-class> >>> <init-param> >>> <param-name>matchOnUriPrefix</param-name> >>> <param-value>true</param-value> >>> </init-param> >>> <load-on-startup>1</load-on-startup> >>> </servlet> >>> >>> <servlet-mapping> >>> <servlet-name>CamelServlet</servlet-name> >>> <url-pattern>/services/*</url-pattern> >>> </servlet-mapping> >>> >>> >>> >> >> >> > > -- > View this message in context: > http://www.nabble.com/How-to-create-a-Servlet-component--tp24909157p24940161.html > Sent from the Camel - Users mailing list archive at Nabble.com. > > -- Claus Ibsen Apache Camel Committer Open Source Integration: http://fusesource.com Blog: http://davsclaus.blogspot.com/ Twitter: http://twitter.com/davsclaus
