Hi,
You can try to create a camel context from the Spring application
context, and put the RouterBuilder into that camel context.
You just need to put the bean's definition into the Spring configuration
like this
<bean id="YourBeanName" class="YourBeanClass" />
Willem
Nawaz wrote:
But still i am getting the same exception
even after including the below line
CamelContext camel = new DefaultCamelContext(context);
in the code.
Is there any other condition to taken care in Bean component?
Regards
Nawaz Ahmed
Claus Ibsen-2 wrote:
Hi
As said before you need to pass your jndi context to CamelContext
JndiContext context = new JndiContext();
context.bind("myBeanId",new SayService());
CamelContext camel = new DefaultCamelContext(context);
camel.addRoutes(new RouteBuilder() {
... inline the route builder
});
camel.start();
On Wed, Oct 21, 2009 at 12:34 PM, Nawaz <[email protected]> wrote:
I am using the Bean element, Where JNDI context is created and it refers
to
the SayService class …
After that below one DSL route is created consisting of BeanRef
Camel component.
On running this configuration, below exception is reported
org.apache.camel.NoSuchBeanException: No bean could be found in
the registry for: myBeanId
Referred this site, but could not get any help.
In what way I can register the bean? Please help me in
this
regard.
Please see the code below:
// Creating the JNDI context.
JndiContext context;
try
{
context = new JndiContext();
context.bind("myBeanId",new SayService());
}
catch(Exception e)
{
e.printStackTrace();
}
from("jms:queue:nq1").
//to("bean:bye")
beanRef("myBeanId","printhello")
.to("jms:queue:nq2");
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--
Claus Ibsen
Apache Camel Committer
Open Source Integration: http://fusesource.com
Blog: http://davsclaus.blogspot.com/
Twitter: http://twitter.com/davsclaus
