Hello, My problem is I do not know the name of the datasource at design time. I use blueprint to create an OSGi bundle which start a RouteBuilder <camelContext id="hermes-journal" trace="false" xmlns="http://camel.apache.org/schema/blueprint";> <package>fr.foo</package> </camelContext> when the routebuilder starts it queries a config database and reads the name of the datasource to use. if the datasource is already defined (by another bundle), the routebuilder creates an endpoint "jdbc:" + datasSourceName. otherwise it creates the datasource, register it on JNDI and creates the endpoint. the problem is to test this algorithm. I can actually with camelTestSuport, before creating the route builder, add a dataSource in the camel registry [1]. it allows me, to test the first case (the datasource already exists)
but I can not test the second case that is to say: create the datasource after starting the routebuilder and register it in the registry. in this case before the creation of routebuilder, the datasource does not exist, (I do not know his name). the road builder starts, reads the configuration, Creates the dataSource and saves it inJNDI if I did getContext().getRegistry(); I can not use "bind" because it is not a method of Registry (but of JndiRegistry). if I use NamingContext InitialContext = new InitialContext(); I can register the datasource. but in JUnit, it creates another JndiRegistry and does not use one created by CamelTestSupport when creating the endpoint, the camel can not find datasource in its registry. This makes sense because InitialContext (); in JUnit, does not retrieved the camel registry. but creates another. While under OSGI InitialContext (); retrieves the registry JNDI and OSGI camel uses it. A + JYT PS: Sorry for my approximative english _____ De : Christian Mueller [via Camel] [mailto:[email protected]] Envoyé : lundi 26 mars 2012 18:59 À : sekaijin Objet : Re: How to register a datasource, on configure() method or constructor of a RoutBuilder ? If you are talking about unit testing, simply override the "createRegistry()" method as in [1]. If you are talking about the real application, simply define the datasource in your spring xml and use the endpoint uri "jdbc:<spring_bean_id_of_your_datasource_bean>". Look at [2] and [3] for an example. [1] https://svn.apache.org/repos/asf/camel/trunk/components/camel-jdbc/src/test/ java/org/apache/camel/component/jdbc/AbstractJdbcTestSupport.java [2] https://svn.apache.org/repos/asf/camel/trunk/components/camel-jdbc/src/test/ java/org/apache/camel/component/jdbc/JdbcSpringAnotherRouteTest.java [3] https://svn.apache.org/repos/asf/camel/trunk/components/camel-jdbc/src/test/ resources/org/apache/camel/component/jdbc/camelContext.xml Best, Christian On Mon, Mar 26, 2012 at 3:06 PM, sekaijin <[hidden email]>wrote: > Hello, > I can not run camel-jdbc in java. > > I defines a route with camel-blueprint, via a road builder (not in XML) > because I know the road to be built when bundle start. > > when starting the bundle, I read a database that contains definitions of > endpoints. with there informations, I build the road. where in the database > I have a record defining an endpoint jdbc datasource I create a datasource > "myDataSourceName" and the uri "jdbc:myDataSourceName" > > in the documentation I've read, I had to do > JndiRegistry reg = super.createRegistry(); > reg.bind("testdb", db); > return reg; > > but I'm in the configure method or in constructor of route builder > I can not call super.createRegistry(); the register already exists > I tried context.getRegistry (); who gets a JndiRegistry but getRegistry() > return a simple Registry. > The bind method does not exist on Registry. > I tried (JndiRegistry) context.getRegistry(); > but I get a CastException. > > public RouteBuilder() > super(); > inUrl = getParameter("input.url"); > //... read configuration datas > DataSourceName = "myDataSourceName"; > > DataSource DS = DataSourceFactory.create(DataSourceName, ....); //using > pooled datasource factory (c3p0) > > JndiRegistry reg = (JndiRegistry) getContext().getRegistry(); > //CastException > reg.bind("myDataSourceName", reg);// > //Or > Registry reg = getContext().getRegistry(); > reg.bind("myDataSourceName", reg);//compil error bind is not method of > Registry > > dsUri = "jdbc:" DataSourceName; > } > > public void configure() { > RouteDefinition r = from(inUrl); > if ("sommeValue".equals(sommeParameter) {} > r.bean(MyBean.class); > //... > r.to("dsUri) > > > > I have a similar problem in JUnit > CamelTestSupport created a camelContext and a Registry > then create the RouteBuilder (calls constructor) > and calls the configure() method > > I've created an object datasource but inpossible to put it in the registry. > > can you help me ? > A JYT > PS: Sorry for my approximative english > > -- > View this message in context: > http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure- method-or-constructor-of-a-RoutBuilder-tp5595165p5595165.html > Sent from the Camel - Users mailing list archive at Nabble.com. _____ If you reply to this email, your message will be added to the discussion below: http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure- method-or-constructor-of-a-RoutBuilder-tp5595165p5595849.html To unsubscribe from How to register a datasource, on configure() method or constructor of a RoutBuilder ?, click <http://camel.465427.n5.nabble.com/template/NamlServlet.jtp?macro=unsubscrib e_by_code&node=5595165&code=amVhbi15dmVzLnRlcnJpZW5Ac2FwLmFwaHAuZnJ8NTU5NTE2 NXwtNDg3MTEzOTE4> here. 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