It depends on your runtime environment, which Registry is used: - org.apache.camel.spring.spi.ApplicationContextRegistry - org.apache.camel.blueprint.BlueprintContainerRegistry - org.apache.camel.impl.CompositeRegistry - org.apache.camel.impl.JndiRegistry - org.apache.camel.core.osgi.OsgiServiceRegistry - org.apache.camel.impl.PropertyPlaceholderDelegateRegistry - org.apache.camel.impl.SimpleRegistry
Best, Christian On Thu, May 17, 2012 at 3:56 PM, sekaijin <[email protected]>wrote: > the response is in my first post > > > ==>CastException > > when you define your camel context Camel create a new Jndi resgisty or un > osgi get de osgi jndiRegistry > > but when you call getContext().getRegistry(); camel do not return this > registry but an registryProxy > that not permit to get the real registry and not have bind method > > A+JYT > > -- > View this message in context: > http://camel.465427.n5.nabble.com/How-to-register-a-datasource-on-configure-method-or-constructor-of-a-RoutBuilder-tp5595165p5711404.html > Sent from the Camel - Users mailing list archive at Nabble.com. >
