Hello All,
I used following route in XML DSL.
The requirement is to read file content , which is a line of string
delimited by '~', depending on specific pattern of a token I need to copy
the file to respective folder with full content. It copies the file but the
content is found only that token on which it checks the condition.
For example:
File content (Full) : userid=1~pass=jayanta~oprncode=ATM~custno=4990000001~
The File that was copied contains only : oprncode=ATM (But actually I need
to get the full content)
Following is the XML DSL ::
-------------------------------------
<route id="route1">
<from uri="file:E:\\bankappfiles\\received?delete=true" />
<log message="Title Name [${body}]"/>
<split stopOnException="true">
<tokenize token="~"/>
<choice>
<when>
<simple> ${in.body} ==
'oprncode=ATM'</simple>
<to
uri="file:E:\\bankappfiles\\atm?noop=true" />
</when>
<when>
<simple>${in.body} ==
'oprncode=NEFT'</simple>
<to
uri="file:E:\\bankappfiles\\neft?noop=true" />
</when>
</choice>
</split>
</route>
Please advice how can I get the full content of the source file in the
copied one?
Thanks in advance,
Jayanta P.
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