Hi Betty/Derek,

Thanks for getting back.

Yes, that's certainly helped.  I'm now confident that my variable also contains the tags in addition to the values.  It was by changing the "." for "@* | node()" that did it.

So my xslt looks like this:
    <xsl:variable name="gml">
      <xsl:copy-of select="@* | node()"/>
    </xsl:variable>
However, I now believe this variable is still a Node-Tree, and not a String.  I need it to be the latter so I can pass the XML excerpt to the Java method I mentioned earlier (using xalan to do so).

Is there a way of casting/translating a node tree into a String?

Best regards,

Andy



Derek Hohls wrote:
And that is not a "trick", but standard XSLT; see:
http://www.dpawson.co.uk/xsl/sect2/N1930.html#d3389e91
as select="." only selects the value (string) inside the tag/s.

  
On 2008/06/27 at 06:48, in message <[EMAIL PROTECTED]>, "Betty Harvey" <[EMAIL PROTECTED]> wrote:
        
Try this for your xsl:copy:

<xsl:copy><xsl:apply-templates select="@* | node()" /></xsl:copy>

<quote who="Andrew Chamberlain">
  
Hi All,

It's quite possible that this is more XSLT-related than Cocoon itself,
but wasn't sure where else to post.

I'm using an XSL transformer and need to capture a tree fragment in the
value of variable ... including the tags themselves.  The reason for
this is because I need to pass the XML excerpt (as a string) to a Java
class which is specifically written to parse it.

I'm trying the following, but this only seems to include the values, and
not the tags:

    <xsl:variable name="gml">
      <xsl:copy-of select="."/>
    </xsl:variable>

Can anyone help?  Is there a trick for this?

Many thanks,

Andy
    



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