Andrew Chamberlain schrieb:
Hi Betty/Derek,
Thanks for getting back.
Yes, that's certainly helped. I'm now confident that my variable also
contains the tags in addition to the values. It was by changing the "."
for "@* | node()" that did it.
So my xslt looks like this:
<xsl:variable name="gml">
<xsl:copy-of select="@* | node()"/>
</xsl:variable>
However, I now believe this variable is still a Node-Tree, and not a
String. I need it to be the latter so I can pass the XML excerpt to the
Java method I mentioned earlier (using xalan to do so).
Is there a way of casting/translating a node tree into a String?
That would be XML serializing. AFAIK XSLT is not capable of this (I
don't know about XSLT 2.0, though). Why do you have to convert the
fragment to a string? Wouldn't it be more straightforward to pass the
fragment to the Java code, so that it doesn't have to be parsed again?
-- Andreas
Best regards,
Andy
------------------------------------------------------------------------
Derek Hohls wrote:
And that is not a "trick", but standard XSLT; see:
http://www.dpawson.co.uk/xsl/sect2/N1930.html#d3389e91
as select="." only selects the value (string) inside the tag/s.
On 2008/06/27 at 06:48, in message <[EMAIL PROTECTED]>, "Betty Harvey" <[EMAIL
PROTECTED]> wrote:
Try this for your xsl:copy:
<xsl:copy><xsl:apply-templates select="@* | node()" /></xsl:copy>
<quote who="Andrew Chamberlain">
Hi All,
It's quite possible that this is more XSLT-related than Cocoon itself,
but wasn't sure where else to post.
I'm using an XSL transformer and need to capture a tree fragment in the
value of variable ... including the tags themselves. The reason for
this is because I need to pass the XML excerpt (as a string) to a Java
class which is specifically written to parse it.
I'm trying the following, but this only seems to include the values, and
not the tags:
<xsl:variable name="gml">
<xsl:copy-of select="."/>
</xsl:variable>
Can anyone help? Is there a trick for this?
Many thanks,
Andy
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