At 16:58 10/09/2014 +1200, Steve Edmonds wrote:
I think the trick is to not calculate the difference/no. samples and keep adding but to calculate the difference and multiply by position over number of samples added to start time.
For the avoidance of doubt, you will see that this is what my original suggestion (two days ago) does.
For a quick test this seems to give times to 0.00 of a second ...
No, it gives times to about *ten* fractional places of a second (0.0000000000), but it may well *display* with less precision - depending on your cell formatting. This is one of the original questioner's misunderstandings.
Got to dash to beat the traffic, but can post the formula when I'm home.
Or see my original reply: " In B2, enter: =B1+(B$6-B$1)/5 and fill this down to B5"!
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