Guess what 1f*5/5==1f (Java; 1 AS float multiplied by 5 divided by 5 is equals 
to 1 as a float)
Everyone not studying computer science won't understand this at first glance 
(and Google has the best explanations) but with Math.abs((1f/5*5)-1)<0.0001 you 
do not have a workaround, but the way it has to be done.... (Die not read the 
thread, just want to explain that you cannot = on floats)

Am 08. Juli 2015 20:42:46 MESZ, schrieb Joel Madero <[email protected]>:
>Sounds to me like normal floating number behavior. I know someone is
>trying
>to document this and explain why it happens (it's a technical reason
>that
>goes beyond my skills) but this seems entirely normal behavior given
>the
>constraints of programming languages generally and hardware in
>particular.
>
>
>Best,
>Joel
>
>P.S. You can see similar issues in other spreadsheet software. This
>seems
>to give some indication as to the reasons why:
>https://support.microsoft.com/en-us/kb/78113 (yes I know it's MSO
>link...just explaining the reason why floating number isn't entirely
>accurate all the time)
>
>On Wed, Jul 8, 2015 at 11:33 AM, Rui Pedro Caldeira
><[email protected]>
>wrote:
>
>> Hey and thanks for your fast answer. This is the data set:
>>
>>   0.000001  0.000001  0.000001  0.000001  0.000001  0.000001 
>0.000001
>> 0.000001  0.000001  0.000001  0.000001  0.000001  0.000001  0.000001
>> 0.000002  0.000003  0.999997  0.999997  0.999997  0.999997  0.999998
>> 1.000001  1.999997
>>
>> Using the formula in the spreadsheet it gives the value: 0.328061419
>(VAR)
>> and 0.5727664611 (STDEV)
>>
>>
>> And yes, i do mean CHISQ.INV :)
>>
>> Thanks, Rui.
>>
>> Cumprimentos,
>> Rui Pedro Caldeira
>>
>> On Wed, Jul 8, 2015 at 7:24 PM, Brian Barker
><[email protected]>
>> wrote:
>>
>> > At 18:44 08/07/2015 +0100, Rui Pedro Caldeira wrote:
>> >
>> >> I'm having some problems with the VAR and STDEV function, when
>executing
>> >> these lines of code. The average is well calculated but the
>remaining
>> two
>> >> return very low, unrealistic and equal values
>(6.93018471335974E-310).
>> >>
>> >
>> > That value is 2^-1027 - which is probably the smallest
>floating-point
>> > value your system can represent without underflow.
>> >
>> > Have you compared the results produced from your data by equivalent
>> normal
>> > formulae in a spreadsheet cell?
>> >
>> > Do you mean CHISQ.INV and not CHISQINV?
>> >
>> > Brian Barker
>> >
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>
>
>-- 
>*Joel Madero*
>LibreOffice QA Volunteer
>[email protected]
>
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