Hi mg,

      `foo [....]` is ambiguous, parser can parse it as index expression or
parse it as method invocation without parentheses, the former is applied to
solve the ambiguity. 

       Similarly, `println [1, 2, 3]` will fail too ;-)

Cheers,
Daniel.Sun




--
Sent from: http://groovy.329449.n5.nabble.com/Groovy-Users-f329450.html

Reply via email to