Thanks
(Berry) A.W. van Halderen wrote: > > On Wed, Aug 15, 2007 at 07:40:12AM -0700, Ishai Borovoy wrote: >> How can I easily get all the nodes that have refer to other node? >> For example I have Node A, B, C. >> A has reference property to C. >> B has reference property to C. >> >> I want to get in some way (by code or by query) all the nodes that >> reference >> properties that refer to C. > > Assuming you use UUIDs (in A and B) and mix:referenable on C: > > Node C; > Set<Node> allNodesThatReferToC = new HashSet<Node>; > for(PropertyIterator iter = C.getReferences(); iter.hasNext(); ) > allNodesThatReferToC.add(iter.nextProperty().getParent()); > > \Berry > -- > Berry A.W. van Halderen [EMAIL PROTECTED] / > [EMAIL PROTECTED] > Disclaimer: the above is the author's personal opinion and is not the > opinion > or policy of his employer or of the little green men that have been > following > him all day. > > -- View this message in context: http://www.nabble.com/References-tf4273547.html#a12167198 Sent from the Jackrabbit - Users mailing list archive at Nabble.com.
