hi,
what you want is 'Node.restore()'. checkout just makes as checked-in
node modifiable.
in your example the 2nd checkout has no effect since the node is
already checked out.
regards, toby
On 12/8/07, Sridhar Raman <[EMAIL PROTECTED]> wrote:
> This is what I have figured out from reading the documentation, and testing:
> The following code,
> Node A = root.addNode("NODEA", "ATYPE");
>
> A.checkout();
> A.setProperty("PROP1", "some value");
>
> A.save();
> A.checkin();
>
> creates a version for the node A, and currently the node is in a read-only
> status.
>
> Now if I were to execute the following code,
> Node A = root.getNode("NODEA");
>
> A.checkout();
> A.setProperty("PROP1", "some other different value");
>
> A.save();
> // NOT DOING ANY CHECK-IN
>
> I expected no new version to be created for node A. And yes, this happens
> as expected.
> But say, I execute this code now,
> Node A = root.getNode("NODEA");
>
> A.checkout();
> System.out.println(A.getProperty("PROP1").getString());
>
> I expected the value "some value" to be printed. This was because, I
> thought the checkout that I do would mean that I get node A's latest
> version. But what is printed is "some other different value".
>
> I somehow found this a bit counter-intuitive. Can someone please clarify my
> doubt?
>
> Thanks,
> Sridhar
>
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