Hi, Andy, 

For query, we have:

String queryUri = "http://xxx.ccc.com:3030/dataset/query";;
Query query = QueryFactory.create(queryString);

QueryEngineHTTP qeHttp = QueryExecutionFactory.createServiceRequest(queryUri, 
query);

ResultSet results = qeHttp.execSelect();


which is perfect.

How about for update?
Do we also have similar things like:

String updateUri = "http://xxx.ccc.com:3030/dataset/update";;
UpdateRequest ur = UpdateFactory.create(updateString);


And then get the handle to execute update? It'd be great if you can come up 
with some code examples.

Thanks
Frank




________________________________
 From: Frank Lee <[email protected]>
To: "[email protected]" <[email protected]> 
Sent: Wednesday, September 26, 2012 1:17 PM
Subject: Re: Remote named graph
 
Thanks, Andy. It made good sense. 

Cheers, 
Frank



________________________________
From: Andy Seaborne <[email protected]>
To: [email protected] 
Sent: Wednesday, September 26, 2012 11:31 AM
Subject: Re: Remote named graph

On 26/09/12 01:06, Frank Lee wrote:
> Thanks for that, Andy.
>
> So, we can't use any existing API (for we've already grabbed the handle of 
> the namedGraph model) to duplicate it, SPARQL/update is the only way to do it.

Mu suggestions were made so as to avoid copying everything onto the 
local machine, and copying it back out again.   Using COPY, only a copy 
within the remote machine is done.  Is that what you are trying to do?

    Andy


>
>
>
> ________________________________
>   From: Andy Seaborne <[email protected]>
> To: [email protected]
> Sent: Tuesday, September 25, 2012 2:34 PM
> Subject: Re: Remote named graph
>
> On 25/09/12 00:33, Frank Lee wrote:
>> Hi, Andy,
>>
>> What will be better way to duplicate existing named graph remotely?
>> Or duplicated many with different URIs. Is there any simple API to
>> use for it? Thanks.
>>
>> Cheers Frank
>
> SPARQL Update:
>
> something like
>
> COPY <g1> To <g2>
>
> for a one to one copy:
>
> or
>
> INSERT { GRAPH <g> { ?s ?p ?o } }
> WHERE { GRAPH ?g { ?s ?p ?o } FILTER ( ?g IN ( <g1>, <g2>, <g3> ) ) }
>
> for many
>
> (untested)
>
>      Andy
>

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