RE: How to filter SPARQL query with a list

[Rob Vesse]

There's no need to do a FILTER(?s IN sub query) and as you have found out this 
is actually illegal SPARQL

You can however put the sub query in directly and get the desired effect. 
SPARQL evaluation is bottom up so the inner query gets evaluated first

Rob


________________________________________
From: Charles Li [charlesqua...@gmail.com]
Sent: 31 August 2013 09:36
To: users@jena.apache.org
Subject: How to filter SPARQL query with a list

Hi, all Jena/SPARQL experts!

I am composing a SPARQL query trying to list all triples whose subjects are
in a list of RdfId's, and this list of RdfId's are from another select
query:

select ?s  ?p  ?o
WHERE
{
   ?s  ?p  ?o
   FILTER(?s in (
                   select distinct ?s WHERE
                   {
                      ?s  ?p  ?o
                      FILTER(contains(str(?o),
"_{000E9C27-150C-480B-9CC7-E23FFC62C90A}"))
                   }
                ) &&
           !(contains(str(?o), "_{000E9C27-150C-480B-9CC7-E23FFC62C90A}"))
          )
}
order by ?s


However, the SPARQL query is not well-format, and it seems that it
doesn't allow another "select" in place for the list of values.

Can someone help me and advice how I can put in a list of RdfId's from
another query (lines 6 - 10)?


Thanks a lot!

- Charles