On 01/09/13 01:39, Charles Li wrote:
Thanks, Rob!
What I really need to do is to query by a given rdf:ID string, since I am
building an RDF/XML traversing tool. My challenge is how to quickly get all
triples whose subject has a given RdfID.
As you know rdf:ID is an RDF/XML artifact and there is no such a triple in
the model whose predicate is "ID". How would up come up with a SPARQL query
to take a string of the rdf:ID input and return all triples whose subject
has the given RdfID?
Any help is greatly appreciated!!!
rdf:ID is not a predicate; it's a syntax for the subject.
If you have rdf:ID="foo"
and the base URI for the data is http://example/xyz/
then the subject is http://example/xyz/foo.
Query with
<http://example/xyz/foo> ?p ?o
Try writing your data out as N-triples to Turtle to see the structure
and the actual URIs.
Andy
- Charles
On Sat, Aug 31, 2013 at 12:16 PM, Rob Vesse <[email protected]> wrote:
There's no need to do a FILTER(?s IN sub query) and as you have found out
this is actually illegal SPARQL
You can however put the sub query in directly and get the desired effect.
SPARQL evaluation is bottom up so the inner query gets evaluated first
Rob
________________________________________
From: Charles Li [[email protected]]
Sent: 31 August 2013 09:36
To: [email protected]
Subject: How to filter SPARQL query with a list
Hi, all Jena/SPARQL experts!
I am composing a SPARQL query trying to list all triples whose subjects are
in a list of RdfId's, and this list of RdfId's are from another select
query:
select ?s ?p ?o
WHERE
{
?s ?p ?o
FILTER(?s in (
select distinct ?s WHERE
{
?s ?p ?o
FILTER(contains(str(?o),
"_{000E9C27-150C-480B-9CC7-E23FFC62C90A}"))
}
) &&
!(contains(str(?o), "_{000E9C27-150C-480B-9CC7-E23FFC62C90A}"))
)
}
order by ?s
However, the SPARQL query is not well-format, and it seems that it
doesn't allow another "select" in place for the list of values.
Can someone help me and advice how I can put in a list of RdfId's from
another query (lines 6 - 10)?
Thanks a lot!
- Charles
