Try the online query validator:
http://www.sparql.org/query-validator.html
Andy
On 31/10/13 15:17, Maria Jackson wrote:
select ?x ?a ?b ?c ?d ?e ?f where {
graph ?r {
?x ?y <CountryZ>
}
graph ?r1{
?x ?y <CountryZ1>
}
?r <saidBy> Tia ;
<saidOn> ?b ;
<saidAt> ?c ;
<confidence> ?d ;
<comment> ?e .
?r1 <saidBy> Astrid.
}
Is the above query to retrieve a person who is linked to two different
countries correct?
I am just curious as to whether it is syntactically accepted by Jena
On Thu, Oct 31, 2013 at 8:45 PM, Joshua TAYLOR <[email protected]>wrote:
On Thu, Oct 31, 2013 at 10:47 AM, Eric Scott <[email protected]> wrote:
You could try something like this:
select ?a?b?c?d?e
where
{
?g a :MyKindaGraph.
graph ?g
{
?r rdf:subject <Mr_X>.
?r rdf:predicate <isPresident>.
?r rdf:object <CountryZ>.
?r saidBy ?a.
?r saidOn ?b.
?r saidAt ?c.
?r confidence ?d.
?r comment ?e
}
}
I think, though I could be wrong, that the point wasn't just to put
the triples _into_ a named graph, but to use a named graph to serve
_as_ the reified triple (or triples). E.g.,
graph ?g { <Mr_X> <isPresident> <CountryZ> }
?g saidBy ?a ; ... ; comment ?e .
This avoids needing three triples for each reified statement, and
makes the queries easier to write. It also makes it easier to provide
meta information about a collection of triples, rather than just a
single reified triple.
//JT
--
Joshua Taylor, http://www.cs.rpi.edu/~tayloj/
