Hi Andy, Yeah, that's pretty close. I originally posted this thread, cause I found myself looking at http://answers.semanticweb.com/questions/10457/calculating-and-extracting-a-substring-in-sparqlagain. All the answers there were close, but just slightly off. I've posted what I now think is the correct answer (thanks in part to your help) at http://answers.semanticweb.com/questions/10457/calculating-and-extracting-a-substring-in-sparql
Tim On Wed, May 14, 2014 at 1:44 AM, Andy Seaborne <[email protected]> wrote: > A form of "localname" can be done in SPARQL without the need for extension > functions: > > REPLACE(str(?uri), '^.*(#|/)', '')" > > which returns the part after the last / or # > > Andy > >
