On 11/01/2017 16:25, Chris Dollin wrote: > > > On 11/01/17 14:55, George News wrote: >> Hi, >> >> I have this literal: >> http://hola^^http://www.w3.org/2001/XMSchema#anyURI > > What do you mean by "have"? A String value, a Literal > value, or what?
I want to get http://hola as a String or as a URI. Better as a URI, but only if it is conforming with the type linked. >> And I want to create a URI from it. Is there any way to do so? > > And do you want an actual URI object or just its spelling? > > Because you can get the spelling of the URI using getLexicalForm. Literal a = (Literal) ResourceFactory.createTypedLiteral("http://hola^^http://www.w3.org/2001/XMSchema#anyURI";, XSDDatatype.XSDanyURI); System.out.println(a.getDatatype()); System.out.println(a.getLexicalForm()); System.out.println(a.getDatatypeURI()); System.out.println(a.getString()); Output: Datatype[http://www.w3.org/2001/XMLSchema#anyURI -> class java.net.URI] http://hola^^http://www.w3.org/2001/XMSchema#anyURI http://www.w3.org/2001/XMLSchema#anyURI http://hola^^http://www.w3.org/2001/XMSchema#anyURI None of them returns "http://hola"; which is the actual URI. > Chris >
