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On Friday, June 27th, 2025 at 7:02 AM, Will McDonald <wmcdon...@gmail.com> 
wrote:

> On Fri, 27 Jun 2025 at 12:32, olivares33561 via users 
> <users@lists.fedoraproject.org> wrote:
> 
> > I am struggling to create a script that generates a series of dates with 
> > special "+%Y.%m.%d" like the following
> > 
> > 2025.06.01
> > 2025.06.01
> > 2025.06.01
> > 
> > I found several examples but can't succeed to get what I want
> > ------
> > 
> > #!/bin/bash
> > start=$1
> > end=$2
> > 
> > start=$(date -d $start +%Y%m%d)
> > end=$(date -d $end +%Y%m%d)
> > 
> > while [[ $start -le $end ]]
> > do
> > echo $start
> > start=$(date -d"$start + 1 day" +"%Y%m%d")
> > done
> > ------
> 
> 
> The date command can't parse dates with periods/dots in this step: 
> start=$(date -d $start +%Y%m%d)
> 
> Example:
> 
> wmcdonald@DESKTOP-9HGJE25:~$ echo $IN
> 2025.07.01
> wmcdonald@DESKTOP-9HGJE25:~$ date -d $IN +%Y%m%d
> date: invalid date ‘2025.07.01’
> wmcdonald@DESKTOP-9HGJE25:~$
> 
> So that step's going to fail. And the while loop can't evaluate the dotted 
> notation strings for greater/less than. The easiest thing to do is strip the 
> dots from the input, then add them back in in the output. This isn't elegant, 
> and someone may provide a better answer but this works:
> 
> #!/bin/bash
> start=$1
> end=$2
> 
> start=$(date -d $(echo $start | sed 's/\./-/g') +%Y%m%d)
> end=$(date -d $(echo $end | sed 's/\./-/g') +%Y%m%d)
> 
> date -d"$start" +%Y.%m.%d
> 
> while [[ $start -lt $end ]]
> do
> date -d"$start + 1 day" +%Y.%m.%d
> start=$(date -d"$start + 1 day" +%Y%m%d)
> done
> 
> wmcdonald@DESKTOP-9HGJE25:~$ ./daterange.sh 2025.07.01 2025.07.16
> 2025.07.01
> 2025.07.02
> 2025.07.03
> 2025.07.04
> 2025.07.05
> 2025.07.06
> 2025.07.07
> 2025.07.08
> 2025.07.09
> 2025.07.10
> 2025.07.11
> 2025.07.12
> 2025.07.13
> 2025.07.14
> 2025.07.15
> 2025.07.16
> 
> 
> 

Yes Sir.  It does the job.  It works but it doesn't print four iterations of 
the date. 
A for loop inside will do it, but I am not sure how to it?

In here,
> do
> date -d"$start + 1 day" +%Y.%m.%d
> start=$(date -d"$start + 1 day" +%Y%m%d)

A for i=1..4 and print four versions of each date. 

But my skills aren't that great.

Best Regards,


Antonio 

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