On Fri, 27 Jun 2025 at 12:32, olivares33561 via users <
users@lists.fedoraproject.org> wrote:
> I am struggling to create a script that generates a series of dates with
> special "+%Y.%m.%d" like the following
>
> 2025.06.01
> 2025.06.01
> 2025.06.01
>
> I found several examples but can't succeed to get what I want
> ------
>
> #!/bin/bash
> start=$1
> end=$2
>
> start=$(date -d $start +%Y%m%d)
> end=$(date -d $end +%Y%m%d)
>
> while [[ $start -le $end ]]
> do
> echo $start
> start=$(date -d"$start + 1 day" +"%Y%m%d")
> done
> ------
>
The date command can't parse dates with periods/dots in this step:
start=$(date -d $start +%Y%m%d)
Example:
wmcdonald@DESKTOP-9HGJE25:~$ echo $IN
2025.07.01
wmcdonald@DESKTOP-9HGJE25:~$ date -d $IN +%Y%m%d
date: invalid date ‘2025.07.01’
wmcdonald@DESKTOP-9HGJE25:~$
So that step's going to fail. And the while loop can't evaluate the dotted
notation strings for greater/less than. The easiest thing to do is strip
the dots from the input, then add them back in in the output. This isn't
elegant, and someone may provide a better answer but this works:
#!/bin/bash
start=$1
end=$2
start=$(date -d $(echo $start | sed 's/\./-/g') +%Y%m%d)
end=$(date -d $(echo $end | sed 's/\./-/g') +%Y%m%d)
date -d"$start" +%Y.%m.%d
while [[ $start -lt $end ]]
do
date -d"$start + 1 day" +%Y.%m.%d
start=$(date -d"$start + 1 day" +%Y%m%d)
done
wmcdonald@DESKTOP-9HGJE25:~$ ./daterange.sh 2025.07.01 2025.07.16
2025.07.01
2025.07.02
2025.07.03
2025.07.04
2025.07.05
2025.07.06
2025.07.07
2025.07.08
2025.07.09
2025.07.10
2025.07.11
2025.07.12
2025.07.13
2025.07.14
2025.07.15
2025.07.16
--
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