Re: [IronPython] c# function that passes arguments by reference

Dino Viehland Fri, 25 Aug 2006 16:53:07 -0700

The Reference object is just a holder so that you can pass it in, and then use it after the call. It has a .Value property that will return you the updated value (or the original if the value hasn’t changed). So x.Value should get you the new value.

From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Frank Kampas
Sent: Friday, August 25, 2006 2:17 PM
To: Discussion of IronPython
Subject: Re: [IronPython] c# function that passes arguments by reference

Ok, that worked but what I got back is not very useful

>>> lpstat = clr.Reference[int](0)
>>> objval = clr.Reference[float](0)
>>> x = clr.Reference[System.Array[float]](System.Array[float]((0,0,0)))
>>> pi = clr.Reference[System.Array[float]](System.Array[float]((0,0,0)))
>>> sl = clr.Reference[System.Array[float]](System.Array[float]((0,0,0)))
>>> dj = clr.Reference[System.Array[float]](System.Array[float]((0,0,0)))
>>> wr.GetResults(lpstat,objval,x,pi,sl,dj)
True
>>> x
<IronPython.Modules.ClrModule+Reference`1[[System.Double[], mscorlib, Version=2.
0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089]] object at 0x0000000000
00002E [Reference(System.Double[])]>
>>> lpstat
<IronPython.Modules.ClrModule+Reference`1[[System.Int32, mscorlib, Version=2.0.0
.0, Culture=neutral, PublicKeyToken=b77a5c561934e089]] object at 0x0000000000000
02F [Reference(1)]>
>>>

The approach I found seems to be more useful if it doesn't have some problem that

would show up for bigger arrays.

>>> wr.GetResults(0,0,(0,0,0),(0,0,0),(0,0,0),(0,0,0))
(True, 1, 13.0, System.Double[](5.0, 4.0, 0.0), System.Double[](0.0, 0.0, -3.062
5), System.Double[](0.0, 0.0, 0.0), System.Double[](0.0, 0.0625, 0.375))

----- Original Message -----

From: Dino Viehland

To: Discussion of IronPython

Sent: Friday, August 25, 2006 5:00 PM

Subject: Re: [IronPython] c# function that passes arguments by reference

You can do:

import System

import clr

clr.Reference[System.Array[int]]( System.Array[int]( (1,2,3) ) )

This breaks down into the array creation:

System.Array[int]( (1,2,3) )

And then passing that to the new instance of clr.Reference.

From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Frank Kampas
Sent: Friday, August 25, 2006 1:43 PM
To: Discussion of IronPython
Subject: Re: [IronPython] c# function that passes arguments by reference

how to I create an array to pass by reference? I assume that your example is creating an integer with a value of 3 to pass by reference.

----- Original Message -----

From: Dino Viehland

To: Discussion of IronPython

Sent: Friday, August 25, 2006 4:06 PM

Subject: Re: [IronPython] c# function that passes arguments by reference

This is the “easy” way to call functions that are passing values by reference. You should be able to pass non-zero values as well as non-empty arrays. The only thing that should disallow this is if there were multiple overloads that resulted in an ambiguous method resolution.

For these cases there is a generic Reference type defined in the CLR module. You can use this:

import clr

x = clr.Reference[int](3)

someObj.someFunction(x)

print x.Value

and Value will be updated after the call.

From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Frank Kampas
Sent: Friday, August 25, 2006 12:58 PM
To: [email protected]
Subject: [IronPython] c# function that passes arguments by reference

If I import a c# function that passes its arguments (integers and arrays)

by reference, the only way I can get it to work is pass zeroes for the integers and

arrays of zero for the arrays. The results for the variables passed by reference return with the function

return. Is that what is supposed to occur?

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