I don't know if that's your problem but indices start at 1 in scilab
(like in matlab).
On 2013-05-07 18:34, MattM wrote:
Hi, Im using the following code:
n=1
q=2
for t=0:1:15
select t
case 0
B(0)=0
else
B(t) = abs(besselj(q,q.*1/15*t)/(q.*1/15*t));
end
end
t2=linspace(0,1,15);
plot2d(t2,B)
To define B at the points t=0,1,2,3...16, however as there is a t on
the
denominator scilab doesn't let me plot this for t=0. I still want to
include
this point however. I have tried using select and cases to define
B(0) as
being equal to zero, however I get an invalid index error.
Thanks
Matt
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