Hi Christophe, first of all let me thank you so much for your time and effort on this.
I was referring to this wiki article from the beginning. http://en.wikipedia.org/wiki/Bicycle_and_motorcycle_dynamics About the points that you have raised, > I guess this is the bicycle seen from behind (or front, no matter), and > that the frame of reference is the bicycle. Yes it is the bicycle seen from behind > You forgot to define w, delta and phi. <http://mailinglists.scilab.org/file/n4030480/CodeCogsEqn4.gif> where r is the approximate radius, w is the wheelbase, θ is the lean angle, δ is the steer angle, and φ is the caster angle of the steering axis > The rotational equilibrium in the frame of reference is just v^2/r/g = > tan(theta). That is true for the rotational equilibrium. But what I have done is deriving an deferential equation describing the system. <http://mailinglists.scilab.org/file/n4030480/CodeCogsEqn-Derive.gif> > You did not specify what you are drawing. In the first xcos schematic what I have shown is how I implemented above equation in xcos. In the second picture what I have shown is the impulse response of the system ( The out put theta to the impulse input delta) Thanks a lot for the effort and I really do appreciate it. Best Gona -- View this message in context: http://mailinglists.scilab.org/Bicycle-Dynamics-tp4030466p4030480.html Sent from the Scilab users - Mailing Lists Archives mailing list archive at Nabble.com. _______________________________________________ users mailing list [email protected] http://lists.scilab.org/mailman/listinfo/users
