Right, and if one follows the thread till the end, how does that apply to diffcode_jacobian ?
-----Original Message----- From: users [mailto:users-boun...@lists.scilab.org] On Behalf Of philippe Sent: Tuesday, October 10, 2017 8:56 AM To: users@lists.scilab.org Subject: Re: [Scilab-users] evaluate matrix in a function Hi, Le 07/10/2017 à 13:05, Hermes a écrit : > how do I declare the functions to be able to evaluate a matrix > variable(Multiple evaluation of a function). Where the first column > corresponds to the first variable of the function. And so on. > is only possible within a "for" cycle? how to declare the function to be > able to use the operator "dot" I'm not sure of what you are asking for. It looks like you want to evaluate a function f on the curve defined by 2 vectors x,y instead of evaluating it on the grid defined by x,y (which is done by feval). If this is what you are searching for you can use something like feval2 below : function z=feval2(x,y,f) // eval f on the curve t->(x(t),y(t)) // and on the grid defined by x,y deff('z=newf(k)','z=f(x(k),y(k))') // x,y are global variables for the "newf" function z=feval(1:length(x),newf) // "newf" is a local variable for "feval2" endfunction then try the example : -->deff('z=f(x,y)','z=x.^2-y.^2') // test function -->x=-3:3;y=x; -->z=feval(x,y,f)// grid evaluation z = 0. 5. 8. 9. 8. 5. 0. - 5. 0. 3. 4. 3. 0. - 5. - 8. - 3. 0. 1. 0. - 3. - 8. - 9. - 4. - 1. 0. - 1. - 4. - 9. - 8. - 3. 0. 1. 0. - 3. - 8. - 5. 0. 3. 4. 3. 0. - 5. 0. 5. 8. 9. 8. 5. 0. -->z=feval2(x,y,f) // curve evaluation z = 0. 0. 0. 0. 0. 0. 0. Best regards Philippe _______________________________________________ users mailing list users@lists.scilab.org http://lists.scilab.org/mailman/listinfo/users _______________________________________________ users mailing list users@lists.scilab.org http://lists.scilab.org/mailman/listinfo/users
