not really when i do it with my pencil, i get to the real values directly, i mean i can turn it like i want till i get the right answers that i need, try it with lambda2?
imean it could work but is it mathematical correct? with best regards / mit freundlichen Grüssen / cordialement Pascal Bühler Qualität-Hardware / Prüfingenieur SAUTER HeadOffice Fr. Sauter AG Im Surinam 55, CH-4016 Basel Telefon +41 (0)61 695 5646 Telefax +41 (0)61 695 5619 http://www.sauter-controls.com DISCLAIMER: This communication, and the information it contains is for the sole use of the intended recipient. It is confidential, may be legally privileged and protected by law. Unauthorized use, copying or disclosure of any part thereof may be unlawful. If you have received this communication in error, please destroy all copies and kindly notify the sender. Before printing out this e-mail or its attachments, please consider whether it is really necessary to do so. Using less paper helps the environment. Von: "Dang Ngoc Chan, Christophe" <christophe.d...@sidel.com> An: Users mailing list for Scilab <users@lists.scilab.org>, Datum: 27.02.2018 11:31 Betreff: Re: [Scilab-users] {EXT} Antwort: Re: [EXTERNAL] Problem with solving this elegantly Gesendet von: "users" <users-boun...@lists.scilab.org> Hello, > De : Pascal Buehler > Envoyé : mardi 27 février 2018 11:20 > > Now for lambda1, insert the number to the matrix, where sigmaxx =-1, sigmayy =5 and tauxy=4 already known is, as a stress tensor > you will get two linear equation like > > -8*v1x+4*v1y=0 > 4*v1x-2*v1y=0 > > normaly an trivial solution, but non of the sovers gave me the correct answer? A=[-8 4 ; 4 -2] b = [0 ; 0] [x0, kerA] = linsolve(A, b) kerA = 0.4472136 0.8944272 x0 = 0. 0. You notice that kerA(2)/kerA(1) = 2 which means that the result is similar to kerA = 1 2 x0 = 0. 0. Which is the excepted solution. Or? -- Christophe Dang Ngoc Chan Mechanical calculation engineer This e-mail may contain confidential and/or privileged information. If you are not the intended recipient (or have received this e-mail in error), please notify the sender immediately and destroy this e-mail. Any unauthorized copying, disclosure or distribution of the material in this e-mail is strictly forbidden. _______________________________________________ users mailing list users@lists.scilab.org http://lists.scilab.org/mailman/listinfo/users
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