Hello,
While updating "help empty" after changes in Scilab 6 about inequality
comparisons with [],
i have found that det([]) is changed:
* 5.5: det([]) => 1
* 6.0: det([]) => 0
I don't know if this modification is intentional.
I am wondering about the added value of this change:
* If we consider the property for square matrices A & B:
det(A*B) = det(A)*det(B) (1)
setting det([])=0 better complies with it. Indeed, since []*B => [],
we have now det([]*B) = det([])*det(B) = 0*k = 0 = det([]) : OK
* In another hand, we should also have :
det(1/A) = 1/det(A) (2)
Since inv([]) => [], setting det([]) => 1 complied with (2),
while det([]) => 0 no longer does it.
Settingdet([]) => [] would comply with both (1) and (2).
Let's note that Octave returns 1.
So, shall we restore det([]) ==1, or keep 0, or set it to [] ?
What's the improvement in changing det([]) to 0 ?
Regards
Samuel
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