Hello,
What do you wan to achieve exactly?
As Stéphane pointed out, the sizes are not the same.
When you assign something like:
A=B;
You have two different situations:
1) size(A)==size(B)
2) size(B)=[1,1]
In the first case, you assign each element of B to each element of A. In
the latter case (which corresponds to your commented line), B is just a
scalar that gets assigned to each element of A.
In the current situation, you are neither in case 1) nor in case 2).
As you have size(NodesMatrix2(i,j+1))=[300,300] and
size(resu(k))=[300,1], you might want to replicate resu(k) 300 times and
fill NodesMatrix2(i,j+1) with these 300 copies. If this what you want to
do, here is the code:
NodesMatrix2(i,j+1)=resu(k)*ones(1,300);
By the way, why do you use "evstr(resu(k))" instead of "resu(k)"?
Antoine
Le 01/06/2018 à 11:45, Stéphane Mottelet a écrit :
It cannot work since
--> size(k)
ans =
300. 1.
--> length(i)*length(j)
ans =
90000.
i.e. NodesMatrix2(i,j+1) has 90000 elements and resu(k) has 300
S.
Le 01/06/2018 à 11:07, Carrico, Paul a écrit :
Dear all
I’ve a submatrix issue on the following example, and I do not
remember (or understand) why : how can I do this ?
(the goal is to extract and to store within a matrix results from an
Ascii file)
Thanks for any help
Paul
###############################################################
mode(0)
clearall
StartNodeLine= 1;
NumberOfNodes= 100;
DimCoordinates= 3;
resu= rand(1000,1);
tic();
NodesMatrix2= zeros(NumberOfNodes,DimCoordinates+1);
i= [1 : NumberOfNodes]'; NodesMatrix2(i,1) =
_evstr_(resu(StartNodeLine + (DimCoordinates+2)*(i-1)+2));
i= [1 : NumberOfNodes]'.*.ones(1,DimCoordinates)';
j= ones(1,NumberOfNodes)'.*.[1 : DimCoordinates]';
k= StartNodeLine + (DimCoordinates+2)*(i-1)+3+j;
a= _evstr_(resu(k));
NodesMatrix2(i,j+1)= _evstr_(resu(k)); /// does not work/
///NodesMatrix2(i,j+1) = 1; // work(basic assignement)/
Duration2= toc()
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