Dear all I found a solution. I get the column echelon form of A by X=rref(A')'. Then the rows' numbers with the non-zero pivot of X are the independent rows' numbers of A.
In this problem 26th row and 27th row are redundant. 26th rows are represented by linear combinations of 24th row and 1st-23rd rows. 27th rows are represented by a linear combination of 25th row and 1st-23rd rows. Best regards. -- Sent from: http://mailinglists.scilab.org/Scilab-users-Mailing-Lists-Archives-f2602246.html _______________________________________________ users mailing list [email protected] http://lists.scilab.org/mailman/listinfo/users
