Hello all,
In Scilab 6.0.1 (and previous versions), norm() does not support %inf
and %nan in the argument:
--> norm([1 %inf])
norm: Wrong value for argument #1: Must not contain NaN or Inf.
--> norm([1 %nan])
norm: Wrong value for argument #1: Must not contain NaN or Inf.
We plan to change this in Scilab 6.0.2, i.e. returning a value instead
of raising based on the following rationale:
since, at least for vectors, we have for finite p
norm(x,p)=sum(abs(x).^p)^(1/p)
we should have, for example,
-%inf case:
--> p=2;x=[1 %inf]; sum(abs(x).^p)^(1/p)
ans =
Inf
-%nan case:
--> p=2;x=[1 %nan]; sum(abs(x).^p)^(1/p)
ans =
Nan
-%inf and %nan case
--> p=2;x=[1 %nan %inf]; sum(abs(x).^p)^(1/p)
ans =
Nan
hence,
norm([1 %inf],p) -> %inf,
norm([1 %nan],p) -> %nan
norm([1 %nan %inf],p) -> %nan
Thank you for your feedback !
S.
--
Stéphane Mottelet
Ingénieur de recherche
EA 4297 Transformations Intégrées de la Matière Renouvelable
Département Génie des Procédés Industriels
Sorbonne Universités - Université de Technologie de Compiègne
CS 60319, 60203 Compiègne cedex
Tel : +33(0)344234688
http://www.utc.fr/~mottelet
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