Ok, so why nested function in help is so complicated:
//nested functions definition
function y=foo(x)
a=sin(x)
function y=sq(x), y=x^2,endfunction
y=sq(a)+1
endfunction
foo(%pi/3)
Couldn't it be formulated like below:
function y1=foo1(x)
a=sin(x);
y1=a^2+1;
endfunction
foo1(%pi/3)
That's why I had problems with my functions and couldn't understand why
it has to be so complicated.
Thank you once more.
Iza
W dniu 10.04.2019 14:10, Rafael Guerra napisał(a):
In your example, why not using a simpler URQ function definition into
fsolve?
For example:
mg = 0.1; h=0.1; l=0.1; L0=0.1;
function y=URQ(q)
e = mg./(2*q);
z= asinh(mg.*h./(2*q.*l.*sinh(e)))+e;
y= mg.*L0./(q.*l)-sinh(2*e-z)-sinh(z)
endfunction
q=1;
y=URQ(q)
Rgds
Rafael
-----Original Message-----
From: users <[email protected]> On Behalf Of Izabela
Wójcik-Grzaba
Sent: Wednesday, April 10, 2019 3:01 PM
To: Users mailing list for Scilab <[email protected]>
Subject: Re: [Scilab-users] Nested function definition
Thank you. Is there a way to use this formulation as an input function
to fsolve? I don't know how to do it.
In my another example I also had a nested function but I managed to
define it in a form like in help page about function. It means that
everything was inside one function. This formulation worked fine in
fsolve, but with my current example I am not able to use it.
Iza
_______________________________________________
users mailing list
[email protected]
http://lists.scilab.org/mailman/listinfo/users
_______________________________________________
users mailing list
[email protected]
http://lists.scilab.org/mailman/listinfo/users
