One solution:
// Run the last (largest):
[ns, seq] = collatz(prime($))
// insert in new zeros vector:
ns = [zeros(prime-1), ns]
// insert seq in new zeros matrix:
seq = [zeros(length(seq), length(ns)-1), seq];
for i = 1:length(prime)-1
// Run collatz to get the new ns:
[nsi, seqi] = collatz(prime(i));
// insert in vector ns and matrix seq:
ns(i) = nsi;
seq(1:nsi, i) = seqi;
end
dispalay ns above seq:
[ns; seq]
Stefan
On 2021-08-15 13:03, Lester Anderson wrote:
Hi Stefan,
Thank you for clarifying the meaning of the error message.
Lester
On Sun, 15 Aug 2021 at 11:59, Stefan Du Rietz <[email protected]
<mailto:[email protected]>> wrote:
Hello Lester,
the problem is that seq in each loop is a vector of increasing length!
Stefan
On 2021-08-15 12:05, Lester Anderson wrote:
> Hi Stefan,
>
> I did try that before, but got an error - "Submatrix incorrectly
defined"
>
> Lester
>
> On Sun, 15 Aug 2021 at 10:56, Stefan Du Rietz <[email protected]
<mailto:[email protected]>
> <mailto:[email protected] <mailto:[email protected]>>> wrote:
>
>
>
> On 2021-08-15 09:00, Lester Anderson wrote:
> > Hello,
> >
> > Basic query. I have a simple code that applies the Collatz
> conjecture
> > equation (3n+1) by running a function and then runs a loop
over the
> > values stored in prime (the first 8 Prime numbers):
> >
> > clear
> >
> > exec('collatz.sci',-1);
> >
> > prime = primes(20);
> >
> > for i = 1:length(prime)
> > [ns, seq]=collatz(prime(i))
> > end
> >
> > As it stands, this just runs to the end (i=8) and the
value 19.
> How can
> > I get the code to write the results of each loop pass into the
> variables
> > ns and seq, such that each contains the results of the 8
passes?
> >
> > Can no longer search the forums online from the website.
> >
> > Thanks
> > Lester
>
>
> // Before the for loop:
> ns = zeros(prime);
> seq = ns;
>
> // Changed for loop
> for i = 1:length(prime)
> [ns(i), seq(i)]=collatz(prime(i))
> end
>
> Regards
> Stefan
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