Hello Jens.
Nothing sophisticated here.
print myVar
is considered by the parser as
print("myVar")
See "Calling function"/item 4.
https://help.scilab.org/docs/6.1.1/en_US/functions.html
S.
Le 06/12/2021 à 10:40, Jens Simon Strom a écrit :
Hi Samuel,
Your solution is quite sophisticated. To me it was confusing to call a
function without the input being bracketed. And on top of this, that a
variable of type /constant/ is accepted as a /string/ within the
function. Scilab seems to be more flexible than I would dare to
imagine before now. However it works fine. Thanks again.
Regards
Jens
-------------------------------------------------------------------------------------------------------------------------------------------------------------
Am 05.12.2021 um 20:02 schrieb Samuel Gougeon:
Le 04/12/2021 à 20:59, Samuel Gougeon a écrit :
So, /unless you need to know the name *inside* printc() for some
unsaid purpose/, what would be the difference between in one hand
[name, mag, arg] = printc(myvar, "myvar")
and on the other hand
name = "myvar";
[mag, arg] = printc(myvar)
?
So, after your mail in private, you actually needs the variable's
name inside the function.
Then, the easiest way to do what you expect could be to pass only the
name:
function printc(name)
execstr("c = "+name)
//Drucken einer komplexen Zahl mit Betrag und Winkel/°
mprintf([name+': %f /_%7.2f°\n'],abs(c), 180/%pi*atan(imag(c),real(c)))
endfunction
--> myVar = 3 - 2*%i
myVar =
3. - 2.i
--> printc myVar
myVar: 3.605551 /_ -33.69°
Regards
Samuel
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Stéphane Mottelet
Ingénieur de recherche
EA 4297 Transformations Intégrées de la Matière Renouvelable
Département Génie des Procédés Industriels
Sorbonne Universités - Université de Technologie de Compiègne
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