Denis suggests to copy contents of URL to a file first before accessing it.
-D
On 7/16/06, Sebastien Arbogast <[EMAIL PROTECTED]> wrote:
I tried that, based on Dennis' proposition:
URL url = this.getClass().getClassLoader().getResource( "/foo" );
try {
File servlet = new File(url.toURI());
getLog().info(servlet.getAbsolutePath());
} catch (URISyntaxException e) {
throw new MojoExecutionException(e.getMessage(),e);
}
But then I got an exception on the first line of the try block:
java.lang.IllegalArgumentException: URI is not hierarchical
I was thinking of using IOUtils to copy the content of foo to another
directory but it seems to be harder than I thought.
2006/7/16, dan tran <[EMAIL PROTECTED]>:
> Thanks
>
> On 7/16/06, Dennis Lundberg <[EMAIL PROTECTED]> wrote:
> >
> > It depends on what you want to do with the resource.
> >
> > I used it with
> > FileUtils.copyURLToFile( url, new File( outputDirectory, filename )
);
> > to copy a resource from within the jar file to the target directory.
> >
> > --
> > Dennis Lundberg
> >
> > dan tran wrote:
> > > Dennis, would you suggestion work? since the resource is in a jar,
> > > and therefore obtaining a "File" object is not possible.
> > >
> > > am I missing something?
> > >
> > > -D
> > >
> > >
> > > On 7/16/06, Dennis Lundberg <[EMAIL PROTECTED]> wrote:
> > >>
> > >> Sebastien Arbogast wrote:
> > >> > In the plugin I'm working on, I have a src/main/resources/foo
> > >> > directory and as a result, when the plugin is packaged, I get a
foo
> > >> > directory at the root of the plugin jar, and that's fine.
> > >> >
> > >> > But now I want to get a java.io.File reference to this foo
directory
> > >> > from inside the code of one of my mojos. How can I do that?
> > >> >
> > >>
> > >> You can get a URL which can then be used to create a file like
this:
> > >>
> > >> URL url = this.getClass().getClassLoader().getResource( "/foo" );
> > >>
> > >>
> > >> --
> > >> Dennis Lundberg
> > >>
> > >>
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> > >>
> > >
> >
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> >
>
>
--
Sébastien Arbogast
http://www.sebastien-arbogast.com
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