It means You cannot object a File object in a jar file, so you stuck i guess
unless I am total wrong
-D
On 7/16/06, Sebastien Arbogast <[EMAIL PROTECTED]> wrote:
And would you do that? I mean, foo is a directory, it contains a whole
file tree. I don't quite get it.
2006/7/16, dan tran <[EMAIL PROTECTED]>:
> Denis suggests to copy contents of URL to a file first before accessing
it.
>
> -D
>
>
> On 7/16/06, Sebastien Arbogast <[EMAIL PROTECTED]> wrote:
> >
> > I tried that, based on Dennis' proposition:
> >
> > URL url = this.getClass().getClassLoader().getResource( "/foo" );
> > try {
> > File servlet = new File(url.toURI());
> > getLog().info(servlet.getAbsolutePath());
> > } catch (URISyntaxException e) {
> > throw new MojoExecutionException(e.getMessage(),e);
> > }
> >
> > But then I got an exception on the first line of the try block:
> > java.lang.IllegalArgumentException: URI is not hierarchical
> >
> > I was thinking of using IOUtils to copy the content of foo to another
> > directory but it seems to be harder than I thought.
> >
> > 2006/7/16, dan tran <[EMAIL PROTECTED]>:
> > > Thanks
> > >
> > > On 7/16/06, Dennis Lundberg <[EMAIL PROTECTED]> wrote:
> > > >
> > > > It depends on what you want to do with the resource.
> > > >
> > > > I used it with
> > > > FileUtils.copyURLToFile( url, new File( outputDirectory,
filename )
> > );
> > > > to copy a resource from within the jar file to the target
directory.
> > > >
> > > > --
> > > > Dennis Lundberg
> > > >
> > > > dan tran wrote:
> > > > > Dennis, would you suggestion work? since the resource is in a
jar,
> > > > > and therefore obtaining a "File" object is not possible.
> > > > >
> > > > > am I missing something?
> > > > >
> > > > > -D
> > > > >
> > > > >
> > > > > On 7/16/06, Dennis Lundberg <[EMAIL PROTECTED]> wrote:
> > > > >>
> > > > >> Sebastien Arbogast wrote:
> > > > >> > In the plugin I'm working on, I have a src/main/resources/foo
> > > > >> > directory and as a result, when the plugin is packaged, I get
a
> > foo
> > > > >> > directory at the root of the plugin jar, and that's fine.
> > > > >> >
> > > > >> > But now I want to get a java.io.File reference to this foo
> > directory
> > > > >> > from inside the code of one of my mojos. How can I do that?
> > > > >> >
> > > > >>
> > > > >> You can get a URL which can then be used to create a file like
> > this:
> > > > >>
> > > > >> URL url = this.getClass().getClassLoader().getResource( "/foo"
);
> > > > >>
> > > > >>
> > > > >> --
> > > > >> Dennis Lundberg
> > > > >>
> > > > >>
> > ---------------------------------------------------------------------
> > > > >> To unsubscribe, e-mail: [EMAIL PROTECTED]
> > > > >> For additional commands, e-mail: [EMAIL PROTECTED]
> > > > >>
> > > > >>
> > > > >
> > > >
> > > >
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> > > >
> > > >
> > >
> > >
> >
> >
> > --
> > Sébastien Arbogast
> >
> > http://www.sebastien-arbogast.com
> >
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> >
> >
>
>
--
Sébastien Arbogast
http://www.sebastien-arbogast.com
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