In my setup the jars are all listed in the manifest but they don't have any
directory prepended. The jar with main is in the same directory as the jars
listed in its manifest. The script that runs it cds to that directory. It
doesn't set classpath since the current directory is normally in it.
If I understand your description, with your setup the jars in the manifest
would each need to have the lib directory prepended to them (classpathPrefix).
The advantage of my method (probably minor) is that I can move the work and lib
directories (since they are the same directory) and it still works. The
disadvantage is that each app has its own copy of the jar files, but that could
be an advantage since I don't have to worry about version issues with shared
jars.
Kalle Korhonen wrote:
Or, do it the Java way: add the libs to the manifest of your executable jar
(http://maven.apache.org/guides/mini/guide-manifest.html, the libs can stay
in your lib dir) and just have the start-up script set the work dir or cd to
the home directory of the app.
Kalle
On Thu, Oct 23, 2008 at 6:36 PM, Rusty Wright <[EMAIL PROTECTED]>wrote:
What about simply adding the jars to the classpath without any path, then
when you run the jar have your script cd into the directory where the jars
are? The jar with main will be in the same directory as its dependencies.
For example, my pom has
<!-- don't add classpath prefix; that way the jar can run -->
<!-- from any directory as long as the executing script -->
<!-- cds into the directory it's in. -->
<!-- <classpathPrefix> -->
<!-- ${classpathPrefix}/cars_download -->
<!-- </classpathPrefix> -->
<plugin>
<artifactId>maven-jar-plugin</artifactId>
<configuration>
<archive>
<manifest>
<addClasspath>true</addClasspath>
<mainClass>
edu.berkeley.ist.cars.download.main.CarsDownloadMain
</mainClass>
</manifest>
</archive>
</configuration>
</plugin>
Then my shell script (unix) looks like
JAVACMD=/usr/jdk/latest/bin/java
FLAVOR=download
RUNDIR=/users/facility/cars_runner/${FLAVOR}
JARFILE=cars_${FLAVOR}.jar
JARPATH=${RUNDIR}/${JARFILE}
# first cd to the directory where everything is.
# the classpath in the jar file doesn't specify the
# full path so we need to be in with the jars.
cd ${RUNDIR}
2>&1 ( ${JAVACMD} -jar ${JARPATH} ) >> ${RUNDIR}/logs/${FLAVOR}.log
Here's my assembly xml file that generates the zip file where all the jars
and shell script go in; this gets extracted on the server where the jar
runs.
<?xml version="1.0" encoding="UTF-8"?>
<assembly>
<id>download</id>
<formats>
<format>zip</format>
</formats>
<includeBaseDirectory>false</includeBaseDirectory>
<baseDirectory>/</baseDirectory>
<moduleSets>
<moduleSet>
<includes>
<include>edu.berkeley.ist:cars_download</include>
</includes>
<binaries>
<unpack>false</unpack>
<useStrictFiltering>true</useStrictFiltering>
<includeDependencies>true</includeDependencies>
<outputDirectory>download</outputDirectory>
</binaries>
</moduleSet>
</moduleSets>
<files>
<file>
<source>src/stuff/scripts/cars_download.sh</source>
<lineEnding>unix</lineEnding>
<filtered>true</filtered>
<outputDirectory>download</outputDirectory>
</file>
<file>
<source>src/stuff/notes/crontab.txt</source>
<lineEnding>unix</lineEnding>
<filtered>true</filtered>
<outputDirectory>download</outputDirectory>
</file>
</files>
</assembly>
Stephen Connolly wrote:
have you had a look at the appassembler-mavn-plugin on mojo?
I use it and antrun and buildhelper to create a zip with batch files and
bash scripts and all the dependencies for projects
-Stephen
2008/10/23 carlos f <[EMAIL PROTECTED]>
jar-with-dependencies is not a practical option for our project so we
have
come up with a custom assembly that generates a zip/tar of:
- our projects jar
- a lib dir with all of our projects dependencies
- bat scripts to execute the jar
However I still need to add all of the jars in the lib to the classpath
when
invoking java in the bat scripts.
Is there any way to have maven add the appropriate dependencies entries
for
the bat script based on the current runtime classpath?
Carlos
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