If you can represent the expected string format as a regular
expression, you can use the replaceAll() function [1] with
back-references:
${url:replaceAll('(http://[a-zA-Z0-9]+:)[a-zA-Z0-9]+(@.*)','$1xxxxx$2')}
original: http://username:p...@host.com
after: http://username:xx...@host.com
Note I have parentheses around the groups I want to keep (the
beginning and end, everything but the password part), then I can
re-insert them using back-references $1 and $2 (i.e. the capturing
groups)
[1]
https://nifi.apache.org/docs/nifi-docs/html/expression-language-guide.html#replaceall
Regards,
Matt
On Wed, Apr 27, 2016 at 3:44 PM, Madhukar Thota
<madhukar.th...@gmail.com> wrote:
> Friends,
>
> I am looking for attributes parsing examples. Any help is appreciated?
>
> I want to get difference between two feilds attributes
>
> 1. let say end - start:
>
> ${end:minus(${start}) is this right way to do it?
> 2. I want to mask password in the url, how can i do it?
>
> example: http://username:p...@host.com to http://username:xx...@host.com
>
> 3. How to parse url encoded post data?
>
> Today i am doing all the conversation using ExecuteScriptProcessor using
> python but it is very slow in processing.
>
> Any help is appreciated.
>
> -Madhu
