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Lisi Reisz wrote:
> On Saturday 04 October 2008 23:04:08 Robert Holtzman wrote:
>>  You're right about x^0
>> of course but your example of x^(1 + -1) doesn't look right. x^(1 + -1)
>> reduces to x^0 not x * 1/x.
> 
> x^0 = 1   x*1/x = 1, so they are the same.  To take concrete examples:  x^2 * 
> x^3 = x^(2+3) = x^5, say 2^2 * 2^3 = 8 * 16 = 128, 2^5 = 128
> 
Which number base are you using?
In base 10, 2^2 * 2^3 = 2^5 = 4 * 8 = 32  ;-)

- --
Mike
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