Thank you all for helping out, it really solved my issue :) On Thu, Mar 30, 2017 at 9:40 PM, Mark Thomas <ma...@apache.org> wrote:
> On 30/03/17 16:56, Addy D wrote: > > On Thu, Mar 30, 2017 at 8:49 PM, Konstantin Kolinko < > knst.koli...@gmail.com> > > wrote: > > > >> 2017-03-30 12:15 GMT+03:00 Addy D <pathfinder2104.w...@gmail.com>: > >>> I can see following in log, while starting tomcat: > >>> > >>> Mar 30, 2017 2:33:22 PM > >>> org.springframework.web.socket.server.support.WebSocketHandlerMapping > >>> registerHandler > >>> INFO: Mapped URL path [/call] onto handler of type [class > >>> org.springframework.web.socket.server.support. > >> WebSocketHttpRequestHandler] > >>> > >>> Same kind of logs are also available when I run my Spring boot > >> application, > >>> in this app I am able to connect to wss://localhost:8443/call. > > <snip/> > > > No my application is not "ROOT", > > The the URL you quote above won't work. > > > i have my application as "myapp" but I > > have a similar (almost same, I am moving spring boot app to tomcat) > > spring-boot application which works fine with embedded tomcat in it with > > the same url, in fact in application startup time, I see "/call" getting > > registered in the tomcat log. as shown below. > > You have two options. > > 1. Rename myapp.war to ROOT.war > > 2. Use wss://localhost:8443/myappp/call to access your service > > I'd also recommend a careful read of the Servlet specification, > particularly section 3.5 along with this page from the Tomcat docs: > http://tomcat.apache.org/tomcat-8.5-doc/config/context.html#Naming > > Mark > > --------------------------------------------------------------------- > To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org > For additional commands, e-mail: users-h...@tomcat.apache.org > >
