I'm trying to set up a "init-param" in Tomcat's main web.xml file (the
one in $CATALINA_HOME/conf/web.xml) that looks similar to the following:
<servlet>
<servlet-name>myServlet</servlet-name>
<servlet-class>path.to.my.Servlet</servlet-class>
<init-param>
<param-name>SOME_XML_FILE</param-name>
<param-value>./conf/myservlet/myxmlfile.xml</param-value>
</init-param>
<load-on-startup>0</load-on-startup>
</servlet>
and in my $CATALINA_HOME/conf/server.xml file, I have the following:
<Host name="mydomain.net" appBase="webapps"
unpackWARs="true" autoDeploy="true"
xmlValidation="false" xmlNamespaceAware="false">
<Context path="" docBase="/home/myuser/public_html/" />
</Host>
My XML file is in $CATALINA_HOME/conf/myservlet/myxmlfile.xml, but
whenever I load this up, Tomcat looks for the file under the
/home/myuser/public_html/ folder.
Is there a way that I can tell tomcat to look for a file that's relative
to the $CATALINA_HOME folder instead of my Context Docbase value? It
would be ideal if the Param-Value had no relation to the Context Docbase
value at all.
Is this even possible with Tomcat?
Thanks in advance for any help anyone can offer.
--
Warm regards,
Jordan Michaels
Vivio Technologies
http://www.viviotech.net/
Open BlueDragon Steering Committee
Adobe Solution Provider
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