Hi, Iam using Tomcat 6. In my applicaion, when Users entered any url like 'www.google.com' then it will check for the status of the User. If he is Inactive, then it will send a http packet to redirect to the particular URL: like "http://192.168.100.125:8080/"; . Tomcat is listening to this port 8080. My question is: how do I get the url from tomcat..? If manually user types the url http://192.168.100.125:8080/ then it is displaying proper page to login. But in this case, Internet User does not know the URL. so...i need to get the URL from Tomcat which is listening to 8080 Port.
Please help me. Thanks in advance. -- View this message in context: http://old.nabble.com/URL-Redirect-in-Tomcat-6-tp26722413p26722413.html Sent from the Tomcat - User mailing list archive at Nabble.com. --------------------------------------------------------------------- To unsubscribe, e-mail: users-unsubscr...@tomcat.apache.org For additional commands, e-mail: users-h...@tomcat.apache.org
